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Start your free trialChris Gauthier
Courses Plus Student 6,434 PointsGetting a range of char's in Java Objects
Hello, the challenge is asking for getting a range of chars. Im not 100% sure how to do that...anybody have a bit of help?
public class ConferenceRegistrationAssistant {
/**
* Assists in guiding people to the proper line based on their last name.
*
* @param lastName The person's last name
* @return The line number based on the first letter of lastName
*/
public int getLineNumberFor(String lastName) {
int lineNumber = 0;
/*
lineNumber should be set based on the first character of the person's last name
Line 1 - A thru M
Line 2 - N thru Z
*/
return lineNumber;
}
}
public class Example {
public static void main(String[] args) {
/*
IMPORTANT: You can compare characters using <, >. <=, >= and == just like numbers
*/
if ('C' < 'D') {
System.out.println("C comes before D");
}
if ('B' > 'A') {
System.out.println("B comes after A");
}
if ('E' >= 'E') {
System.out.println("E is equal to or comes after E");
}
// This code is here for demonstration purposes only...
ConferenceRegistrationAssistant assistant = new ConferenceRegistrationAssistant();
/*
Remember that there are 2 lines.
Line #1 is for A-M
Line #2 is for N-Z
*/
int lineNumber = 0;
/*
This should set lineNumber to 2 because
The last name is Zimmerman which starts with a Z.
Therefore it is between N-Z
*/
lineNumber = assistant.getLineNumberFor("Zimmerman");
/*
This method call should set lineNumber to 1, because 'A' from "Anderson" is between A-M.
*/
lineNumber = assistant.getLineNumberFor("Anderson");
/*
Likewise Charlie Brown's 'B' is between 'A' and 'M', so lineNumber should be set to 1
*/
lineNumber = assistant.getLineNumberFor("Brown");
}
}
2 Answers
Jennifer Nordell
Treehouse TeacherHi there! I can see that you've worked on this really hard and thought about it a lot. However, I think you might be at the point where you've overthought this a bit. The biggest hint to this challenge is in this comment that is in the beginner code.
/*
IMPORTANT: You can compare characters using <, >. <=, >= and == just like numbers
*/
So if I write this pseudocode, let's see if you can get it:
if the first letter of the lastName is less than or equal to 'M'
assign the value of 1 to lineNumber
else
assign the value of 2 to lineNumber
return lineNumber;
Don't forget that you can use the charAt
method on a string to say which character of the string you want to look at. I hope this helps, but let me know if you're still stuck!
Chris Gauthier
Courses Plus Student 6,434 PointsThanks, got it. The trick was that char's can be compared like numbers..that's a nifty trick, thanks :)