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Start your free trialSam Bui
878 Pointsget stuck at squared.py challenge
Hi, I am doing this challenge, this is what it ask:
Use try and except on this one. You might have to not use the else block. Write a function named squared that takes a single argument. If the argument can be converted into an integer, convert it and return the square of the number (num ** 2 or num * num). If the argument cannot be turned into an integer (maybe it's a string of non-numbers?), return the argument multiplied by its length.
I have try several methods but nothing works and i don't really know what wrong with my code, if you could show me, that would be great.
Thank
# EXAMPLES
# squared(5) would return 25
# squared("2") would return 4
# squared("tim") would return "timtimtim"
def squared(num):
num = input('> ')
try:
square = int(num)
return square ** 2
except ValueError:
return num * len(num)
1 Answer
Alexander Davison
65,469 PointsYou did great!
But why are you capturing user input? The challenge didn't ask for that.
Just remove this line:
num = input('> ')
And your code passes
I hope this helps
~Alex
Sam Bui
878 PointsSam Bui
878 PointsHi Alexander, thank you for your help, it works just like you say :) At first I thought I need an input function to get arguments and totally forget I can do that with squared(num): :| now when I look back, It make perfectly sense. I don't what I was thinking back then LOL :D