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iOS Functions in Swift Adding Power to Functions Function Parameters

Andrew Bergsma
Andrew Bergsma
880 Points
Posted by Andrew Bergsma
Andrew Bergsma
880 Points

functions in swift a modulo b return remainder ?

func getRemainder(a value: Int, b divisor: Int) -> Int { let remainder = a % b return remainder }

// what am I doing wrong here?

functions.swift 
// Enter your code below



func getRemainder(a value: Int, b divisor: Int) -> Int {
let remainder = a % b
return remainder
}

1 Answer

Matthew Long
Matthew Long
28,407 Points
Matthew Long
Matthew Long
28,407 Points

You pretty much have it except it looks like you mixed up the local and external names for your parameters:

func getRemainder(value a: Int, divisor b: Int) -> Int {
  let remainder = a % b
  return remainder
}

I like to think of it as the first parameter name (or the outside name) is the external name that you use outside the function. Which makes the other name the local name that you use inside the function. Hopefully that clears things up.