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iOS Functions in Swift Adding Power to Functions Function Parameters

Halyna Buriachenko
PLUS
Halyna Buriachenko
Courses Plus Student 1,868 Points

Function in Swift

Hello. I'm not sure what I'm doing wrong. Help;)

In this task we're going to write a simple function that takes two numbers and returns the remainder of dividing one number by the other.

Step 1: Declare a function named getRemainder that takes two parameters, aand b, both of type Int, and returns the value, also of type Int, obtained by carrying out the operation a modulo b. In case you've forgotten, the modulo operator is also called the remainder operator.

Step 2: The local names of the parameters are convenient but they make it hard to figure out the meaning of the function when we call it. Add two external names - value, for the first parameter and divisor for the second.

functions.swift
// Enter your code below
func getRemainder(a value: Int, b divisor: Int) -> Int {
let operation = a % b
return operation
}

1 Answer

The external names should go first, so if you flip those around it should work!!!! Everything else looks good!

func getRemainder(value a: Int, divisor b: Int) -> Int {
  let operation = a % b
return operation
}
``