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iOS Swift Collections and Control Flow Control Flow With Loops For In Loops

Neymat Kakar
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Neymat Kakar
iOS Development Techdegree Student 786 Points

For loop

Inside the body of the loop, we're going to use the multiplier to get the multiple of 6. For example, if the multiplier is 1, then the multiple is 1 times 6, which is equal to 6.

Once you have a value, append it to the results array. This way once the for loop has iterated over the entire range, the array will contain the first 10 multiples of 6.

loops.swift
// Enter your code below
var results: [Int] = [1]
///let multiplier


for multiplier in 1...10 {
print("\(multiplier*6)")
}
Neymat Kakar
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.a{fill-rule:evenodd;}techdegree
Neymat Kakar
iOS Development Techdegree Student 786 Points

// Enter your code below var results: [Int] = [1] ///let multiplier

for multiplier in 1...10 { print("(multiplier*6)") } Note: The above is the code that i wrote which didn't work. If anyone could help me out here plz?

1 Answer

Steven Deutsch
Steven Deutsch
21,046 Points

Hey Naimatullah Muhammad,

You're close! Right now you're just using the wrong method. We don't want to print the values, we want to add them to the results array. You can do this by calling the append method on the results array and passing it the value you want to add to it.

Example:

var results: [Int] = []
let newValue = 10
results.append(newValue)

Hope this helps you solve the challenge, Good Luck

Neymat Kakar
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.a{fill-rule:evenodd;}techdegree
Neymat Kakar
iOS Development Techdegree Student 786 Points

var results: [Int] = [] let newValue = 10 results.append(newValue)

for multiplier in 1...10 { print("(multiplier*6)") }

note: So i tried this code but it doesn't work as i said in my other comment, could you find an error in it?

Joel Martin
Joel Martin
2,799 Points

Hi Neymat, the code Steven provided wasn't for you to copy/paste it for the the challenge. It was to show you which function you should be using instead of "print".

You need to use what he's trying to teach you and apply it to your challenge.