Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialJuan Jimenez
4,389 PointsFizzBuzz
It took me an hour to solve FizzBuzz but it checked out. My code was as follows
for _ in 0...n {
if n % 3 == 0 && n % 5 != 0 {return("Fizz")}
else if n % 5 == 0 && n % 3 != 0 {return("Buzz")}
else if n % 3 == 0 && n % 5 == 0 {return("FizzBuzz")}
}
It worked, but I was just curious if there is anything in here that should be improved.
func fizzBuzz(n: Int) -> String {
// Enter your code between the two comment markers
// End code
return "\(n)"
}
1 Answer
Kevin Tanner
3,385 PointsIf you changed the order of your if statement so you calculate for if it is divisible by 3 and 5 first then you donβt need to have checks for if it is not divisible by 3 or 5.