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Start your free trialAananya Vyas
20,157 Pointsfizzbuzz
i had the same logic given in the solution video before seeing it ... i used switch case instead of if..else..if it didnt work and gave the same error then as it is now i tried changing it to return but again shows the same problem that the logic for either fizz or buzz is wrong!
func fizzBuzz(n: Int) -> String {
// Enter your code between the two comment markers
for n in 1...100 {
if (n % 3 == 0) && (n % 5 == 0){
return "FizzBuzz"
} else if (n % 3 == 0 ){
return "Fizz"
} else if (n % 5 == 0) {
return "Buzz"
} else {
print ( n )
}
}
// End code
return "\(n)"
}