Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Python Basics (2015) Letter Game App Even or Odd Loop

Posted by Robbie Bagley
Robbie Bagley
2,189 Points

even.py

I can't figure out why this doesn't't work. I thought I accounted for all cases. I would appreciate any help. Thank you.

even.py 
import random

start = 5
def even_odd(num):
    while start == True:
        num = random.randint(1,99)
        if num % 2 == 0 and num != 0:
            print("{} is even".format(num))
        else:
            print("{} is odd".format(num))
        start -= 1       
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

1 Answer

Jennifer Nordell
seal-mask
STAFF
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher
Jennifer Nordell
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher

Hi there! First, and foremost, you were not intended to alter the even_odd function, but rather just call it. You will call it and pass in the random number that you generated. When the number is even it will return true, otherwise, it will return false.

Also, note that start will never be explicitly equal to True. We start start with a value of 5. Here is where it's important to know the difference between True and "truthy" and False and "falsey". While start is a value greater than 0, it will be considered "truthy", but not necessarily explicitly equal to True. However, when start reaches 0, it will be "falsey".

You can use while(start):. This simply means while the value of start is "truthy" continue the loop.

I hope this helps, but let me know if you're still stuck! :sparkles:

Robbie Bagley
Robbie Bagley
2,189 Points

Alright, last step but it's a big one. Make a while loop that runs until start is falsey. Inside the loop, use random.randint(1, 99) to get a random number between 1 and 99. If that random number is even (use even_odd to find out), print "{} is even", putting the random number in the hole. Otherwise, print "{} is odd", again using the random number. Finally, decrement start by 1. I know it's a lot, but I know you can do it!

Thank you again for you reply! I'm still having problems figuring out what to do. I tried to follow the directions above.