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Python Python Basics (2015) Letter Game App Even or Odd Loop

Posted by Mehmet Colakoglu
Mehmet Colakoglu
1,297 Points

even.py

It says wrong number of prints

even.py 
import random
def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2
start = 5
while start == True:
    num = random.randint(1, 99)
    a = even_odd(num)
    if a:
        print("{} is odd".format(num))
    else:
        print("{} is even".format(num))
    start = start - 1

1 Answer

Christopher Shaw
seal-mask
PLUS
.a{fill-rule:evenodd;}techdegree seal-36
Christopher Shaw
Python Web Development Techdegree Graduate 58,248 Points
Christopher Shaw
.a{fill-rule:evenodd;}techdegree seal-36
Christopher Shaw
Python Web Development Techdegree Graduate 58,248 Points

There are two places you are going wrong.

  1. The while loop is not running. Change the condition to while start !=0. This will give the right number of prints, but:
  2. You are outputting them the wrong way around, i.e it would say 66 is odd. The conditions need to switched around.
while start != 0:
    num = random.randint(1, 99)
    if even_odd(num):
        print("{} is even".format(num))
    else:
        print("{} is odd".format(num))
    start = start - 1