even.py

Question

Not sure why it keeps telling me I have the wrong number of prints \n other times it tells me on the 3rd task that I'm no longer in agreement with 1st task

even.py

import random
start = 5
def even_odd(num):
  start = 5
  while start is truthy:
    if num % 2 is 0:
      print("{} is even".format(num))
      continue
    else:
      print("{} is odd".format(num))
      continue
    start -= 1

Answer 1 · 2016-02-18T05:27:01Z

February 18, 2016 5:27am

When the challenge starts out, he gives you the even_odd function. He wants you to use that to check the random number you generate in the loop. So everything you write should be outside of that function.

Secondly, in your while loop, you have while start is truthy but you just need while start. That checks truthiness.

thirdly, when it gets to the continue statements it skips the decrementing of the start variable. You don't need the continue statements. If/else are exclusive so if your program goes down one path, it will not go down the other.

Lastly, in the code you posted, you're not generating a random number like he asks. Here is an example of one way to do this:

import random

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

start = 5

while start:
  random_num = random.randint(1, 99)
  if even_odd(random_num):
    print("{} is even".format(random_num))
  else:
    print("{} is odd".format(random_num))
  start -= 1

Welcome to the Treehouse Community

Looking to learn something new?

David Wright

David Wright

even.py

1 Answer

Zach Swift

Zach Swift

David Wright

David Wright