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Start your free trialJohn Wetherbee
1,467 Pointseven_odd(number)
Thank you in advance for your help!
John
def even_odd(number):
number = input("> ")
if number % 2 == 0:
print("False")
else:
print("True")
1 Answer
johngross
5,439 PointsYou don't need to get user input the test supplies a number to even_odd() when you click check work. Also print should be return.
def even_odd(number):
if number % 2 == 0: # Even numbers won't have a remainder.
return(True)
else:
return(False)
John Wetherbee
1,467 PointsJohn Wetherbee
1,467 PointsThank you very much John!!!
Have a great week!!!
John