Even_Odd Loop

Question

My attempt to solve a code challenge is not panning through. Please help! 
Code Challenge:
Treehouse starter code provided:
def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2
Code challenge tasks:
First task:
For this challenge, we're going to need to use the random library. Add an import to the top of your file to bring it in.
Second task:
Here's another easy step.
Make a new variable, outside of the even_odd function, named start that's assigned to the number 5.
Third task:
Make a while loop that runs until start is falsey.
Inside the loop, use random.randint(1, 99) to get a random number between 1 and 99.
If that random number is even (use even_odd to find out), print "{} is even", putting the random number in the hole. Otherwise, print "{} is odd", again using the random number.
Finally, decrement start by 1.
```even.py
import random
start = 5
while start:
    even_odd(start)
    start -= 1
def even_odd(num):
    num = random.randint(1, 99)
    # If % 2 is 0, the number is even.
    if num % 2:
        print("{} is even".format(num))
    else:
        # Since 0 is falsey, we have to invert it with not.
        return not num % 2
        print("{} is odd".format(num))
even_odd(num)
```

Krishna Pratap Chouhan · Answer

Firstly you dont have to write even_odd function yourself. The starter code given is sufficient to implement the functionality and no additional code is needed there.
python
def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

The above code will return opposite of expression 'num%2'.
you have to import random which will be used to get the radom-number-generator.
python
import random

And create a variable 'start' with value 5.
python
start = 5

finally write a while loop that loop through the non-zero value of start variable.
python
while start:
    #some code here.

Inside the loop:
+ get a random number between 1 and 99 using random.randint(1,99)
+ print if the number is even or odd using format function
```python
random number
num = random.randint(1,99)
checking if number is even or odd
if even_odd(num):
printing the number as per the result.
print('{} is odd/even'.format(num))
```
Final code:
```python
def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2
import random
start = 5
while start:
    num = random.randint(1,99)
    if even_odd(num):
        print('{} is even'.format(num))
    else:
        print('{} is odd'.format(num))
    start -= 1
```

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Idris Abdulwahab

Idris Abdulwahab

Even_Odd Loop

1 Answer

Krishna Pratap Chouhan

Krishna Pratap Chouhan

Idris Abdulwahab

Idris Abdulwahab

Krishna Pratap Chouhan

Krishna Pratap Chouhan