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Start your free trialGilang Ilhami
12,045 PointsEven or odd loop
Well this one os pretty compicated Why is task 1 not passing?
import random
start = 5
while True:
num = random.randint(1, 99)
if num = even_odd():
print ("{} is even".format(num))
else:
print("{} is odd".format(num))
start -= 1
else:
return False
def even_odd(num):
# If % 2 is 0, the number is even.
# Since 0 is falsey, we have to invert it with not.
return not num % 2
1 Answer
Tim Rach
Full Stack JavaScript Techdegree Student 25,127 Points- YouΒ΄re not passing anything to even_odd(num) but it expects an argument. - if num = even_odd(): -> if even_odd(num):
- Make a while loop that runs until start is falsey - so -> while start:
This will help you through
import random
start = 5
def even_odd(num):
return not num % 2
while start:
num = random.randint(1, 99)
if even_odd(num):
print("{} is even".format(num))
else:
print("{} is odd".format(num))
start -= 1