even or odd loop

Question

The error message I am getting is "Wrong number of prints". Any idea what he problem could be?
```even.py
import random
start = 5
def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2
while start == 5:
    asd = random.randint(1, 99)
    if even_odd(asd):
        print("{} is even".format(asd))
    else:
        print("{} is odd".format(asd))
    start -= 1
```

Jason Anders · Answer

Hey Dav, 
The problem lies with the condition you set for the while loop. You have while start == 5 which will run the loop only once, as the decrement will make the next iteration equal to 4. Other than that, your code is all correct. :thumbsup:
The challenge want the loop to run all 5 times, so the condition you need will be > 0. This way with each loop the value will decrement by one until the start variable is zero.
Below is the corrected code. I hope it'll make sense. :)
```python
import random
start = 5
def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2
while start > 0:
    asd = random.randint(1, 99)
    if even_odd(asd):
        print("{} is even".format(asd))
    else:
        print("{} is odd".format(asd))
    start -= 1
```
Keep Coding! :dizzy:

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Dav Wal

Dav Wal

even or odd loop

1 Answer

Jason Anders

Jason Anders

Dav Wal

Dav Wal

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