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Start your free trialRyan Walton
1,298 PointsEven and odd Task 3/3 Help!! (Task 1 is no longer working)
I do not know where i am going wrong with the code.
import random
start = 5
def even_odd(num):
# If % 2 is 0, the number is even.
# Since 0 is falsey, we have to invert it with not.
return not num % 2
while start_number > 0:
random_num = random.randint(1, 99)
answer = even_odd(random_num)
if answer == 0:
print("{} is even".format(answer))
start -= 1
sys.exit()
else:
print("{} is odd".format(answer))
start -= 1
sys.exit()
1 Answer
Krishna Pratap Chouhan
15,203 PointsCouple of things...
import random
def even_odd(num):
# If % 2 is 0, the number is even.
# Since 0 is falsey, we have to invert it with not.
return not num % 2
start = 5
# in the condition you probably meant 'start' not start_number
#while start_number > 0:
while start > 0:
random_num = random.randint(1, 99)
answer = even_odd(random_num)
#even_odd is returning not of 0, so its one, i'd rather suggest to check it with true or false. something like [if answer==True:]
if answer == 1:
#its the random number that is to be proved as even or else otherwise
print("{} is even".format(random_num))
#start -= 1
#we shouldn't use exit() function, because it terminates the program, rather just break the loop
#sys.exit()
#you dont have to 'break' it either. The loop is suppose to run 5 times
#break
else:
#its the random number that is to be proved as even or else otherwise
print("{} is odd".format(random_num))
#start -= 1
#sys.exit()
#break
#if we are doing something in both the conditions we can rather specify it outside the loop itself(although is not the problem, just gives a better look)
start -= 1
Ryan Walton
1,298 PointsRyan Walton
1,298 Pointsi fixed up the naming of "start_number" to "start", didn't seem to do the trick