Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Python Basics (2015) Letter Game App Even or Odd Loop

Drew Greene
Drew Greene
5,086 Points
Posted by Drew Greene
Drew Greene
5,086 Points

Even and odd loop

Having trouble with this one. I have tried changing several things and looked through the past questions people have asked but can't figure it out. Any ideas?

even.py 
import random

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

start = 5

while start > 0:
    result = even_odd(random.randint(1, 99))
    if result == 0
        print("{} is even".format(result))
    else:
        print("{} is odd".format(result))
    start -= 1
Drew Greene
Drew Greene
5,086 Points
Drew Greene
Drew Greene
5,086 Points

Also, it's telling me that Task 1 is no longer passing

1 Answer

Steven Parker
Steven Parker
231,236 Points
Steven Parker
Steven Parker
231,236 Points

Since it re-checks task 1 first, it says that if there is a syntax error.

In this case it is because there is no colon at the end of the "if" statement.

Fixing that will pass the challenge, but you might want to know that to test something for "truthy" you only need to name it, so you could just write "while start:".

This also goes for testing boolean values, so you could write "if result:".