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Start your free trialAlejandro Byrne
2,562 PointsError says "Oops! it looks like Task 1 in no longer working!", why? Don't know what I'm doing wrong.
Can someone help me with my code? Not sure what is making it not work...
import random
def even_odd(num):
# If % 2 is 0, the number is even.
# Since 0 is falsey, we have to invert it with not.
return not num % 2
start = 5
while start = True:
num = random.randint(1, 99)
if even_odd(num) = True:
print("{} is even".format(num))
else:
print("{} is odd".format(num))
start -= 1
2 Answers
Chris Freeman
Treehouse Moderator 68,441 PointsYour code is very close. "Task 1 no longer passing" indicates an introduced syntax error.
The condition statements need to use compare ("==") and not assignment ("=").
start
(a number) will never be equivalent to True
, but it can be "truthy". When checking if start
is "truthy", simply use while start
.
Alexander Davison
65,469 PointsFirst of all, start
is never either True or False. It is "truthy"... It's kind of weird, but the simple answer to line 10
is to remove the = True
part.
Keep in mind that 0, None, an empty string, an empty list, and other empty things are falsey and all other values (except booleans) are truthy.
Line 12
where it says if even_odd(num) = True:
is causing a Syntax error as well. Python thinks you are trying to assign a variable called if even_odd(num)
to the value of True. But, of course, you are trying to compare values. TO test equality you should use the double-equals operator (the equality operator). It looks like this: ==
I hope this helps. If you continue to fail, please respond. Thanks! ~Alex
Alejandro Byrne
2,562 PointsAlejandro Byrne
2,562 PointsThanks! it worked. I knew about the '==' just forgot how to check for 'truthy'.