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Start your free trialSorawit Kongnurat
1,284 PointsError cannot find symbol for M
Java is the first programming language I am learning. (I actually forgot everything I learnt in Swift, even then I was still in the early stages.) I don't know if this is only me but I have been having more and more problem understanding the course. Could this be because I am learning new things, and is this a good thing to have?
import java.io.Console;
public class ConferenceRegistrationAssistant {
public int getLineFor(String lastName) {
/* If the last name is between A thru M send them to line 1
Otherwise send them to line 2 */
Console console = System.console();
String lastNameString = console.readLine("Enter your lastname: ");
char name = lastNameString.charAt(0);
return name;
if (name <= M) {
int line = 1;
return line;
} else {
int line = 2;
return line;
}
}
}
3 Answers
Lee Geertsen
Java Web Development Techdegree Student 16,749 PointsYou have to put M between quotes
if (name <= 'M')
Andie Rocca
1,151 PointsAs Lee said you have to put the char M in quotes. Also you shouldn't return name because your program is expecting you to return an int. If you return a char it should either give an error or caste the char to int (giving its ascii value). Also recall that Strings have a compare() method in Java by which you can find whether one string comes later alphabetically than another string.
int compareTo(String anotherString) Compares two strings lexicographically. int compareToIgnoreCase(String str) Compares two strings lexicographically, ignoring case differences. http://docs.oracle.com/javase/7/docs/api/java/lang/String.html
The int returned by compareTo and compareToIgnoreCase symbolizes whether the string comes before the other string or after alphabettically.
str1.compareTo(str2) will return an integer > 0 if str1 is "greater than" str2, an integer < 0 if str1 is "less than" str2, and 0 if str1 = st2.
Sorawit Kongnurat
1,284 PointsThis might be the way to solve it but I never knew this from the tutorial or was it in the eariler part of the course?
Andie Rocca
1,151 PointsI'm not sure I haven't done that course. I learned Java in school. I just thought that might help since its simpler than taking the first char out of the string.
Sorawit Kongnurat
1,284 PointsLook like I solved it. Yay! However, I have misunderstand the question again... getLineFor is already executed. What I needed to do was if (lastName.chartAt(0) <= 'M')...
I feel like I'm so bad at programming ... Even explaining what I just done is hard.
Grigorij Schleifer
10,365 PointsHi Sorawit,
look here, I explained the challenge in little bit there.
https://teamtreehouse.com/community/cant-succeed-that-challenge
To be honest, the course is not easy at all. I am also a programming beginner and Java is my first step into this new world :) Take your time. Donยดt try to run through the lessons and solve the challenges to complete the course. I rewatch many videos in the Java track, because I feel that I need more time to grasp the whole logic.
Donยดt give up and you will get better, but it will need time and patience ...
If you need more help or motivation, let me know ...
Grigorij
Sorawit Kongnurat
1,284 PointsThank you I solved the problem but I had to look around to get an idea. I didn't know that I could just pass string. (I was trying to find the string and more it harder for myself) Yes, I won't give up.
Thank you
Sorawit Kongnurat
1,284 PointsSorawit Kongnurat
1,284 PointsAs Andie said the answer the answe is till wrong. Thank you for the fix on M though. I should have seen it in the question.