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JavaScript Build a Two-Dimensional Array

Ben S
Ben S
5,638 Points
Posted by Ben S
Ben S
5,638 Points

Empty card array declaration

Is there any specific reason why card is first declared as an empty array and then the values are pushed to it, as opposed to declaring it with the values included?

for (let i = 0; i < suites.length; i++) {
    for (let j = 0; j < ranks.length; j++) {
        const card = [];
        card.push(ranks[j], suites[i]);
        deck.push(card);
    }
}

vs

for (let i = 0; i < suites.length; i++) {
    for (let j = 0; j < ranks.length; j++) {
        const card = [ranks[j], suites[i]];
        deck.push(card);
    }
}

1 Answer

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

I expect the video uses separate steps to clearly illustrate that the values are being put into an array, and then that array is being added to another one. You can make the whole process even more compact by eliminating the intermediate variables entirely:

for (let i = 0; i < suites.length; i++) {
    for (let j = 0; j < ranks.length; j++) {
        deck.push([ranks[j], suites[i]]);
    }
}

And it can be even further compacted by using array methods instead of loops:

var deck = suites.map(s => ranks.map(r => [r, s])).reduce((d,c) => [...d, ...c]);

But as you see, the more compact you make it, the less obvious what it is doing becomes.