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Python Python Basics (2015) Number Game App Squared

Posted by Kristian Woods
Kristian Woods
23,414 Points

Does the return statement not allow for in-built function to be used within it?

I have two different solutions for this challenge, yet, the the second solution doesn't work. Why?

The only difference I made, was to put the arguments into their own variable. So I think it must be the return statement? Or something else I'm not picking up on

Thanks in advance

squared.py 
# EXAMPLES
# squared(5) would return 25
# squared("2") would return 4
# squared("tim") would return "timtimtim"

def squared(num):
    try:
        number = int(num)
        return n ** 2
    except ValueError:
        string_length = len(num)
        return num * string_length



squared(4)

# top code works - BOTTOM code doesn't work

def squared(num):
    try:
        return int(num) ** 2
    except ValueError:
        return num * len(num)



squared(4)

1 Answer

Ryan S
Ryan S
27,276 Points
Ryan S
Ryan S
27,276 Points

Hi Kristian,

Your second solution works fine for me. I copied and pasted your code and it passed.

But your first solution doesn't pass because you are using an undefined variable 'n' in your first return statement.