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Python Python Basics (2015) Letter Game App Exiting

Alex Rodriguez
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Alex Rodriguez
Front End Web Development Techdegree Student 20,810 Points
Posted by Alex Rodriguez
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Alex Rodriguez
Front End Web Development Techdegree Student 20,810 Points

Din't get an exit?

Here is my code:

import sys

start_movie = input("Start movie? ")

if start_movie != "n" or start_movie != "N": print("Enjoy the show!") else: sys.exit()

The code challenge keeps telling me that start_movie didn't exit but I thought that is what sys.exit() is for? Am I missing something?

Thank you

2 Answers

Nathan Tallack
Nathan Tallack
22,160 Points
Nathan Tallack
Nathan Tallack
22,160 Points

This is all about the OR evaluation.

Read your code. You are saying:

not n OR not N

Now remember how an OR works. The second it matches one it does not even check for the other. So if I had 4 OR statements in a row if it matches the first one it won't even check for the other three.

So, if an "N" is input, it will never be true because the != 'n' will evaluate as true. Understand.

Try doing it another way. Consider my code below:

import sys

start_movie = input("Start movie? ")

if start_movie == "n" or start_movie == "N":
    sys.exit()
else: 
    print("Enjoy the show!")

If it is n OR if it is N then exit, otherwise print. n or N would be true, everything else would be false.

I think they made this challenge just so we can all make the same mistake you (and I for that matter) did when we encounter it. Tough way to teach us, but effective. ;)