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Python

Posted by Melvin Mescudi
Melvin Mescudi
2,066 Points

Difficulty looping input string prompt to repeat until I get the appropriate value

Trying to get my code to keep retrying until I get a valid input 

# Age 18+ Check year to confirm age

while True:
    try:
        age = int(input("\nWhat year were you born? "))
    except  ValueError or NameError:
        print("*Please enter 4 digit format. Try again")
    if age >= int(2004):
        print("Sorry, but you don't seem to meet the age requirements :( Please try again.. \n")
    if age <= int(2004):
        print("\nWelcome oh wise one!...")
    break
Sekhar Gopisetty
Sekhar Gopisetty
1,938 Points
Sekhar Gopisetty
Sekhar Gopisetty
1,938 Points

The issue I see is that you are attempting to convert the user-input to int - which can throw an exception and will cause the loop to end.

I've changed it a bit, and using isnumeric() to test if the conversion will succeed or not. 

while True:

    age = 0
    stringage = input("\nWhat year were you born? ") #store user input in a separate variable
    if stringage.isnumeric(): #check if the value is numeric
        age = int(stringage)
    else: 
        print("*Please enter 4 digit format. Try again")

    if age == 0: 
        continue;
    if age >= int(2004):
        print("Sorry, but you don't seem to meet the age requirements :( Please try again.. \n")
    if age <= int(2004):
        print("\nWelcome oh wise one!...")
    break

1 Answer

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

Here's a few hints:

  • you can't combine error types with logic ("or"), you'll need two "except" statements
  • everything involving "age" should be done inside the "try" block
  • the inequality test that results in "sorry...." should probably be a "less than" instead of "greater"
  • once you change the comparison, you won't need a separate test for 0
  • literal digits are already numbers and don't need explicit "int" conversions