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684 PointsDidn't understand that question
Hey! I choose a number that is even and i returned True exacly how is asks. what i did wrong? thanx!
def even_odd(4):
return True
2 Answers
Jennifer Nordell
Treehouse TeacherHi there! When defining a function/method the thing in parentheses must be a valid variable name. What the challenge instructions mean is that there will be a number sent into that function/method. You are not to send the number yourself. You can think of a parameter as a variable declaration for the scope of the function you're defining. Once the function ends, the variable will not be accessible any more. Let's take a look at some pseudo code, but I'm going to give you a valid first line here.
def even_odd(num):
#if num is evenly divisible by two (check the hints on the instructions for the modulus operator)
#return True
#otherwise
#return False
Try again with these hints in mind! Good luck!
Ammar Fatihallah
7,417 PointsThe problem with your code is that you're not suppose to include a number, you were suppose to include a var because the number that's given isn't always going to be 4. You also should have done an if loop to check if the var is even or not by using the modulo (%) and check if it equals 1, and if so, return a boolean. Here is the correct code as explained:
def even_odd(a):
if a % 3 == 1:
return True
else:
return False
Hope this clears things out :)
Jennifer Nordell
Treehouse TeacherHi Ammar! I've changed your comment to an answer to let the original poster be able to mark it "Best Answer" if they so desire. And while your code does pass the challenge, it will fail for certain data. If I run the number 2 through your code, it returns False. I have reported this oversight to Support.
Thank you for helping out in the Community!
Ammar Fatihallah
7,417 PointsThank you for mentioning that out so everyone could know :)
or porat
684 Pointsshukran illak ammar!
Ammar Fatihallah
7,417 Pointsafuan ;)
or porat
684 Pointsor porat
684 Pointsthanx jennifer!