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Java Java Basics Getting Started with Java Strings, Variables, and Formatting

MLUNGISI NGQEBE
PLUS
MLUNGISI NGQEBE
Courses Plus Student 1,152 Points
Posted by MLUNGISI NGQEBE
MLUNGISI NGQEBE
Courses Plus Student 1,152 Points

define a string variable firstname

hi i am getting errors please help me.

Name.java 
// I have setup a java.io.Console object for you named console
public class Name{
  public static void main(Strings []args){
    Console console= System.console();
    String name="Ben";
    console.printf("hi i am %s\n",name);
    console.printf("%s is learning",name);
  }}
Jason Anders
Jason Anders
Treehouse Moderator 145,860 Points
Jason Anders
Jason Anders
Treehouse Moderator 145,860 Points

Duplicate post(s) deleted from the Community. Please refrain from multiple posting for the same question

Thank-you
Jason ~Treehouse Community Moderator

2 Answers

Livia Galeazzi
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PLUS
.a{fill-rule:evenodd;}techdegree seal-36
Livia Galeazzi
Java Web Development Techdegree Graduate 21,083 Points
Livia Galeazzi
.a{fill-rule:evenodd;}techdegree seal-36
Livia Galeazzi
Java Web Development Techdegree Graduate 21,083 Points

You don't need to create a class and a main method. In this challenge, just write the lines that go inside the main method. As it says in the comments, you also shouldn't create a console object. There is already one and you can just use it.

For the first task just write the variable declaration. It should be a single line of code. Your variable should be called firstName, not name or anything else.

Task 2 should be a second line of code, which you then should change slightly for the third task. At no point should you have more than two lines of code. Just follow the instructions exactly and you'll be fine.

Jan Oberreiter
Jan Oberreiter
78,020 Points
Jan Oberreiter
Jan Oberreiter
78,020 Points

first thing I can see ... you write Strings ... with an "s" at the end ... but it is always String ... without the "s" ... 

public static void main(String[] args) {