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Python Python Basics (2015) Number Game App Even or Odd

Posted by Christian Atiles
Christian Atiles
1,969 Points

def even_odd (number): if number % 2 == 0 : return True else: return False

what him I doing that it is not working???

even.py 
def even_odd (number):
if number % 2 == 0 :
    return True
else:
    return False
Michael Caveney
Michael Caveney
50,144 Points
Michael Caveney
Michael Caveney
50,144 Points

Have you double-checked indentation? That looks off to me, maybe move everything under the function definition to the right?

EDIT: Yeah, it's definitely your indentation.

2 Answers

jason chan
jason chan
31,009 Points
jason chan
jason chan
31,009 Points

that should be right. please check spacing.

Michael Caveney
Michael Caveney
50,144 Points
Michael Caveney
Michael Caveney
50,144 Points

Oh yeah, did you indent using a mix of spaces and tabs? That might have done it.

Keyer Soze
PLUS
Keyer Soze
Courses Plus Student 1,068 Points
Keyer Soze
Keyer Soze
Courses Plus Student 1,068 Points

Well the Problem is that the code is not like that a take a time to to understand it should be like this. I think the exercise is not clearly!!!

import random
start = 5
def even_odd(num, cont):
    while cont:
        rand = random.randint(1, 99)
        if rand % 2 == 0:
            print("{} is even".format(rand))
        else:
            print("{} is odd".format(rand))
        cont-=1

    return num % 2

even_odd(5 #you chan change to the value you want
, start)

Hope I help!!!