Debugging the Code

Question

import random
def even_odd():
    start = 5
    while start >= 0:
        num = int(random.randint(1, 99))
        if num%2 == 0:
            print('{} is even'.format(num))
        else:
            print('{} is odd'.format(num))
        start -= 1
```even.py
import random
def even_odd():
    start = 5
    while start >= 0:
        num = int(random.randint(1, 99))
        if num%2 == 0:
            print('{} is even'.format(num))
        else:
            print('{} is odd'.format(num))
        start -= 1
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
```

Stuart McIntosh · Answer

Hi there, you may have misread the question. You need to write the while loop outside of the odd_even function and make a call to check odd or even. somethings along the lines below...
```Python
import random
def even_odd(num):
    return not num % 2
start = 5
while start > 0:
   # get the randon number 
    # call odd_even on the number
    # print out if odd or even
```
Hope that helps you finish

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jasonshi

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Debugging the Code

1 Answer

Stuart McIntosh

Stuart McIntosh