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Start your free trialYevgeny Yermakov
10,979 PointsCreating a service
Can’t pass the final task of this challenge. I’ve been trying to pass it for the past couple of hours but nothing seems to work. Tried many different options but still no success. Still can’t figure out where my mistake is.
And this is the error message that I get: ./MainActivity.java:13: error: cannot find symbol service.startService(); ^ symbol: method startService() location: variable service of type TwitterService 1 error
Any help would be very appreciated. Thanks!
public class TwitterService extends Service {
TwitterClient twitterClient = new TwitterClient();
TwitterThread twitterThread;
@Override
public void onCreate() {
twitterThread = new TwitterThread();
twitterThread.start();
}
@Override
public IBinder onBind(Intent intent) {
return null;
}
@Override
public int onStartCommand(Intent intent, int flags, int startId){
Message message = Message.obtain();
twitterThread.twitterHandler.sendMessage(message);
return START_REDELIVER_INTENT;
}
class TwitterThread extends Thread {
TwitterHandler twitterHandler;
@Override
public void run() {
Looper.prepare();
twitterHandler = new TwitterHandler();
Looper.loop();
}
}
class TwitterHandler extends Handler {
@Override
public void handleMessage(Message msg) {
twitterClient.update();
stopSelf();
}
}
}
public class MainActivity extends Activity {
Button button;
private TwitterService service;
@Override
public void onCreate(Bundle savedInstanceState) {
setContentView(R.layout.activity_main);
button = (Button) findViewById(R.id.update_button);
button.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v){
service.startService();
service.stopSelf();
}
});
}
}
1 Answer
Ben Deitch
Treehouse TeacherHey Yevgeny!
We don't start Services explicitly. We start them by creating a new Intent that points to the Service, and then calling the 'startService' method (of the Activity) while passing in the Intent.
@Override
public void onClick(View v){
Intent intent = new Intent(MainActivity.this, TwitterService.class);
startService(intent);
}
Hope that helps!
Yevgeny Yermakov
10,979 PointsYevgeny Yermakov
10,979 PointsAh! Now I see. Thanks a lot for your help, Ben! It worked! :—)