Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialLucas Easley
1,038 PointsCreate a new method named drive
I've been stuck on this question for a while(below). What does Craig mean by "passing in a 1 for the default."
Of course, another user of the code just wrote and asked "Where'd that drive method go! I loved that method, can you put it back please?" Sigh...Well thanks to method overloading we can pretty easily bring the method back
Create a new method named drive that accepts no arguments. It should call the newer drive method passing in a 1 for the default.
class GoKart {
public static final int MAX_BARS = 8;
private String color;
private int barCount;
private int lapsDriven;
public GoKart(String color) {
this.color = color;
}
public String getColor() {
return color;
}
public void charge() {
barCount = MAX_BARS;
}
public boolean isBatteryEmpty() {
return barCount == 0;
}
public boolean isFullyCharged() {
return MAX_BARS == barCount;
}
public void drive(int laps) {
lapsDriven += laps;
barCount -= laps;
}
public void drive(int){
drive = 1;
}
}
2 Answers
Steven Parker
231,269 PointsTo create a method "that accepts no arguments", the definition should have nothing in the parentheses ("drive()
").
And to "call the [other] drive method passing in a 1" would simply be drive(1);
Lucas Easley
1,038 PointsThank you, i just got it. That was a tough one!