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Start your free trialDionte Barnes
10,140 PointsCreate a for loop that logs the numbers 5 to 100 to the console. Use the console.log() method to log a value
for ( let i = 5; 5 < 100; i++ ) {
console.log (i);
}
5 Answers
Joseph Yhu
PHP Development Techdegree Graduate 48,637 PointsLook at your code again; you have 5 < 100 instead of i < 100. Also it's from 5 to 100 inclusive, i.e. 100 should also be logged to the console.
Raechel Kelso
6,037 Pointsfor ( let i = 5; i <= 100; i++ ) { console.log( 100 ); }
I also stuck on this, im not sure what im missing.
Raechel Kelso
6,037 Pointsfor ( let i = 5; i <= 100; i++ ) { console.log( i ); }
I GOT ITTTT! finally.
Tom Nguyen
33,500 PointsMy solution:
for(let i=5; i<101; i++){
console.log(i);
}
Warren Nash
5,032 Pointscan u explain why changing 100 to 101 worked plz
Josh Drummonds
1,230 Pointsi had the exact same code, but 101 was 100. I dont understand how your version worked but mine didn't
Hina K.
4,806 Pointsfor (let i = 5; i <= 100; i++) {
console.log(i) ;
}
Moyosore Banjoko
10,204 PointsMy solution.
for (let count = 5; count <= 100; count++) { console.log(count); }
Joseph Yhu
PHP Development Techdegree Graduate 48,637 PointsJoseph Yhu
PHP Development Techdegree Graduate 48,637 PointsNot sure why I got -2 points when my information was perfectly accurate and clear....
Joseph Yhu
PHP Development Techdegree Graduate 48,637 PointsJoseph Yhu
PHP Development Techdegree Graduate 48,637 PointsSo I will get several thumbs down unless I explicitly post the correct answer?
"...you have 5 < 100 instead of i < 100.":
*
5
should bei
."...100 should also be logged to the console.":
*
<
should be<=
.Hopefully that makes it even more obvious why the answer was wrong. Hint: Look at what I've surrounded with '*'s.