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Start your free trialCody Munster
1,710 PointsContinuing a loop if an index is equal to a value
Sorry for the noob question, I am having trouble with one of the quiz questions. I cant seem to find a way to bypass index 0 if it contains the string "a" in a loop. I want to do this with an if statement if possible...
Thanks
def loopy(items):
# Code goes here
1 Answer
Krishna Pratap Chouhan
15,203 PointsYou can treat a string like a list. so to check a particular index on string, simply use string[index].
def loopy(items):
for item in items:
if item[0]=='a':
continue
else:
print(item)
Cody Munster
1,710 PointsCody Munster
1,710 PointsThanks mate much appreciated!