Continue task - Python Basic

Question

Dear reader,
I run the followig code in python shell and it runs perfectly:
items = [1,2,3,4,5,6,7]
def loopy(items):
       for item in items:
        if item == 1:
            continue
        print(item)
loopy(items)
While the attached task code gives me always an error
```breaks.py
def loopy(items):
    # Code goes here
    for item in items: 
        if item == "a":
          continue
          print(item)
```

Tobias Helmrich · Accepted Answer

Hey Ion,
I see two problems with your code. Firstly you should check the item's index 0 and secondly you have to print the other items in an else block. Right now you're printing the item when the item is "a".
The working code should look like this:
python
def loopy(items):
    # Code goes here
    for item in items: 
        if item[0] == "a":
          continue
        else:
          print(item)

Good luck! :)

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Ion Hustiuc

Ion Hustiuc

Continue task -> Python Basic

1 Answer

Tobias Helmrich

Tobias Helmrich