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Jt Miller
1,242 PointsConfused on challenge
This is what it tells me to do and i have 0 clue what it is trying to tell me.
Same idea as the last one. My loopy function needs to skip an item this time, though. Loop through each item in items again. If the character at index 0 of the current item is the letter "a", continue to the next one. Otherwise, print out the current member. Example: ["abc", "xyz"] will just print "xyz".
def loopy(items):
# Code goes here
1 Answer
Rich Zimmerman
24,063 PointsTake it step by step. you know you want to loop through the items... within the loop you want to check what the character is at index 0 (the first character in the string), and if it is "a", skip it... otherwise print it
def loopy(items):
# loop through the items
for item in items:
# check the character at index 0 and skip it if its 'a'
if item[0] == 'a':
continue
else:
# else print item
print(item)
Jt Miller
1,242 PointsJt Miller
1,242 PointsOk thank you makes sense still kinda lost on the continue function but the rest is clear
Rich Zimmerman
24,063 PointsRich Zimmerman
24,063 Points"continue" in loops basically skips the remainder of the code block and goes to the next iteration of the loops.
For example, say we want to loop through the numbers 1-5 and print out everything but the number 4.