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Start your free trialjose rodriguez
16,524 PointsCompiler is telling me that there is a "(" missing but it looks fine to me can someone tell me what I am doing wrong?
the output is telling me that on line 25 it is missing a "(" and is pointing to the first "n" under the normalizeDiscountCode. then it does not recognize the method in the call in the following methond.
public class Order {
private String itemName;
private int priceInCents;
private String discountCode;
public Order(String itemName, int priceInCents) {
this.itemName = itemName;
this.priceInCents = priceInCents;
}
public String getItemName() {
return itemName;
}
public int getPriceInCents() {
return priceInCents;
}
public String getDiscountCode() {
return discountCode;
}
private void String normalizeDiscountCode( String discountCode ){
this.discountCode = discountCode.toUpperCase();
}
public void applyDiscountCode(String discountCode) {
this.discountCode = normalizeDiscountCode(discountCode);
}
}
public class Example {
public static void main(String[] args) {
// This is here just for example use cases.
Order order = new Order(
"Yoda PEZ Dispenser",
600);
// These are valid. They are letters and the $ character only
order.applyDiscountCode("abc");
order.getDiscountCode(); // ABC
order.applyDiscountCode("$ale");
order.getDiscountCode(); // $ALE
try {
// This will throw an exception because it contains numbers
order.applyDiscountCode("ABC123");
} catch (IllegalArgumentException iae) {
System.out.println(iae.getMessage()); // Prints "Invalid discount code"
}
try {
// This will throw as well, because it contains a symbol.
order.applyDiscountCode("w@w");
}catch (IllegalArgumentException iae) {
System.out.println(iae.getMessage()); // Prints "Invalid discount code"
}
}
}
1 Answer
james south
Front End Web Development Techdegree Graduate 33,271 Pointsin your definition of normalize you have 'void String'. it's one or the other. since you are not returning anything with this method, remove String and leave void, which means this method doesn't return anything. if you were returning a string, then you would put String instead of void.
jose rodriguez
16,524 Pointsjose rodriguez
16,524 PointsI did that and it gives me "Incompatible types: void can not be converted to String"