Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialGabrielle Lamarche
8,587 PointsCode not working | JS Getter
I've made it as readable as possible and can't seem to figure out why this isn't giving me the desired values? If anyone has a shorter solution, that would also be helpful! Thank you
class Student {
constructor(gpa, credits){
this.gpa = gpa;
this.credits = credits;
}
stringGPA() {
return this.gpa.toString();
}
get level () {
if (this.credits > 90) {
return 'Senior';
} else if (this.credits <= 90 && this.credits > 61 ) {
return 'Junior';
} else if (this.credits <= 60 && this.credits >= 31) {
return 'Sophomore';
} else if (this.credits <= 30) {
return 'Freshman';
}
}
}
const student = new Student(3.9);
1 Answer
Antti Lylander
9,686 PointsYou should change your last 'else if' to 'else' only. Remember that 'else' does not need any condition.
Or to make it even simpler, just use 'if' for all the lines. In addition, check what your method returns when the student has 61 credits :)
Like this:
if (condition1) {return 'condition 1 is true'}
if (condition2) {return 'condition 2 is true'}
Now, if the first condition will be true, the second will not be checked at all because 'return' exits the code block.
Gabrielle Lamarche
8,587 PointsGabrielle Lamarche
8,587 PointsThank you!