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Python Python Basics (2015) Letter Game App Even or Odd Loop

Code Challenge solution not passing

I am not sure what to say because the code doesn't work and I'm not sure why. But any help would be appreciated.

I believe the problem with the code is in the expression: If even_odd(num) == True:

I tried using "True", True and it still did not pass.

I tested the even_odd(num) function and it returns either True or False

even.py
import random
start = 5
while bool(start) == True:
    num = random.radiant(1,99)
    if even_odd(num) == "True":
        print("{} is even".format(num))
    else:
        print("{} is odd".format(num))

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

2 Answers

Steven Parker
Steven Parker
231,248 Points

You have more than one issue. Here's a few hints:

  • "True" (with quotes around it) is a string, not a boolean value
  • "radiant" should actually be "randint"
  • You never need to compare a boolean against True, just use it directly
  • So your test can be simply "if even_odd(num):"
  • You don't need to convert a number to a boolean to check for zero, zero is "falsey"
  • So your loop can be simply "while start:"
  • Remember to reduce the value of start each time through the loop, or it will never end!

I'll bet you can get it now without an explicit spoiler. :wink:

Thank you Steven for the help. Those were great hint without giving too much away. I tried it again an it worked! I need to get used to the implicit Boolean values in the logic and looping statements. I think my original version was closer or a lot cleaner, because the version I posted looked sloppy.

I also found out I am supposed to have the function above or before the code being executed. Apparently you can only call a function if it comes before your code.

Please help me.