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Arun Patel
1,180 PointsCheck Work is not happening and getting error "Reload".
Check Work is not happening and getting error "Reload". This has happened multiple times. It is not showing any error as well for the code.
import random
start = 5
def even_odd(num):
# If % 2 is 0, the number is even.
# Since 0 is falsey, we have to invert it with not.
return not num % 2
while True:
x = random.randint(1, 99)
y = even_odd(x)
if y == 'True':
print("{} is even".format(x))
else:
print("{} is odd".format(x))
start -= 1
3 Answers
Chris Howell
Python Web Development Techdegree Graduate 49,702 PointsHello Arun Patel
It looks like your while loop is an infinite loop, so your code never finishes. So the challenge eventually ends it itself.
Im just giving you a hint because its better for your learning if you find the problem and understand what happened than me giving you the answer.
Let me know if that helps, or if you are still stuck on what to do. :)
Arun Patel
1,180 PointsHi Chris,
Thanks for the inputs. I was suspecting the same but still thought it would be shown as an error rather than the Code Check getting stuck and showing Reload Challenge. Will check again.
Chris Howell
Python Web Development Techdegree Graduate 49,702 PointsYeah many of the challenges don't always provide the most useful error messages. But its kind of good because it makes you have to go step by step through your code and helps you learn to debug.
If its possible for you to do, 1 thing you can do is copy your code from the challenge and run it locally on your own machine if you have python installed. Sometimes youll have to provide your own sample data, because you wont always know what the challenge passes in on submission. But if you have an idea, you will get a better error with Python's stack trace on error. :)
Arun Patel
1,180 PointsThanks Chris. I was able to fix the code and the challenge completed. I even tried in locally on my PC.
import random
start = 5 def even_odd(num): # If % 2 is 0, the number is even. # Since 0 is falsey, we have to invert it with not. return not num % 2
while start != False: x = random.randint(1, 99) y = even_odd(x) if y == True: print("{} is even".format(x)) else: print("{} is odd".format(x)) start -= 1
Chris Howell
Python Web Development Techdegree Graduate 49,702 PointsYes! In other languages using a while True is considered a bad practice. But in Python you see it used quite often. But you just have to make sure the moment you write your while True its immediately an infinite loop. so the next statement you should write after that is your condition that will break you out of that loop or cause the loop to end.
Or just use a condition in place of the True at the start of the while if that makes sense.
Glad you got it to pass!