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Start your free trialjun cheng wong
17,021 PointsCheck answer for question 2
Hi, I am not quite sure my answer is accurate. Can anyone take a look at it?
-- Generate a report that lists a patron's first name, email and loan count for loans that haven't been returned.
SELECT first_name AS "First Name",
email,
COUNT(*) AS "Outstanding loans"
FROM patrons INNER JOIN
(
SELECT patron_id FROM loans_south WHERE returned_on IS NULL
UNION ALL
SELECT patron_id FROM loans_north WHERE returned_on IS NULL
)
AS patronsWhoHaveNotReturnedTheBooks ON patrons.id =
patronsWhoHaveNotReturnedTheBooks.patron_id
GROUP BY patrons.first_name;