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Python Python Basics (2015) Letter Game App Even or Odd Loop

Zac Longanecker
Zac Longanecker
1,900 Points
Posted by Zac Longanecker
Zac Longanecker
1,900 Points

Challenge task: even.py

import random start = 5

def even_odd(num): # If % 2 is 0, the number is even. if num % 2 == 0: print("{} is even").format(num) # Since 0 is falsey, we have to invert it with not. return not num % 2 else: print("{} is odd").format(num)

while start > 0: num = random.randint(1, 99) even_odd(num) start -= 1

even.py 
import random
start = 5

def even_odd(num):
    # If % 2 is 0, the number is even.
    if num % 2 == 0:
        print("{} is even").format(num)
        # Since 0 is falsey, we have to invert it with not.
        return not num % 2
    else:
        print("{} is odd").format(num)


while start > 0:
    num = random.randint(1, 99)
    even_odd(num)
    start -= 1

2 Answers

AJ Salmon
AJ Salmon
5,675 Points
AJ Salmon
AJ Salmon
5,675 Points

Printing formatted strings should look like this:

>>> print("Example string number {}".format("1"))
'Example string number 1'
#.format is called inside of the print function, and enclosed in its parentheses

Also, this challenge wants you to call even_odd and check it inside the while loop. So It should follow this structure:

import random

start = 5

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

while start > 0:
    ran_num = random.randint(1, 99)
    #check to see if even_odd(ran_num) is == to 0. If it is:
        print("{} is odd".format(ran_num))
    #otherwise:
        print("{} is even".format(numb))
    #then decrease start by 1

Hope this helps!

AJ Salmon
AJ Salmon
5,675 Points
AJ Salmon
AJ Salmon
5,675 Points

Happy to help :)