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Start your free trialnick beck
3,625 PointsChallenge Task 3 of 3 Replace the hard coded values in the output with the name and email values from the contacts ar
i don't know what else to do from here ? what am i missing ?
<?php
//edit this array
$contacts[] = [
'name' => 'Alena Holligan',
'email' => 'alena.holligan@teamtreehouse.com',
];
$contacts[] = [
'name' => 'Dave McFarland',
'email' => 'dave.mcfarland@teamtreehouse.com',
];
$contacts[] = [
'name' => 'Treasure Porth',
'email' => 'treasure.porth@teamtreehouse.com',
];
$contacts[] = [
'name' => 'Andrew Chalkley',
'email' => 'andrew.chalkley@teamtreehouse.com',
];
echo "<ul>\n";
//$contacts[0] will return 'Alena Holligan' in our simple array of names.
echo "<li>" . $contacts[0]['name'] . ":" . $contacts[0]['email']. "</li>\n";
echo "<li>" . $contacts[1]['name'] . ":" .$contacts[1]['email']."</li>\n";
echo "<li>" . $contacts[2]['name'] . ":" . $contacts[2]['email']."</li>\n";
echo "<li>" . $contacts[3]['name'] . ":" . $contacts[3]['email']." </li>\n";
echo "</ul>\n";
1 Answer
Simon Coates
28,694 Pointsyou're a victim of spacing. There's an space prior to one of li closing tags and you should check whether you need spaces around the ":" being output. It worked for me with the following:
echo "<ul>\n";
//$contacts[0] will return 'Alena Holligan' in our simple array of names.
echo "<li>" . $contacts[0]['name'] . " : " . $contacts[0]['email']. "</li>\n";
echo "<li>" . $contacts[1]['name'] . " : " .$contacts[1]['email']."</li>\n";
echo "<li>" . $contacts[2]['name'] . " : " . $contacts[2]['email']."</li>\n";
echo "<li>" . $contacts[3]['name'] . " : " . $contacts[3]['email']."</li>\n";//EXTRA SPACE WAS ON THIS LINE
echo "</ul>\n";
nick beck
3,625 Pointsnick beck
3,625 Pointsthanks heaps. it was doing my head in.