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JavaScript Object-Oriented JavaScript Working with Classes in JavaScript Adding methods to classes

Challenge Task 2 of 2 Inside the stringGPA() method, convert the value of the gpa string and return it.

Challenge Task 2 of 2

Inside the stringGPA() method, convert the value of the gpa property to a string and return it.

adding_methods.js
class Student {
    constructor(gpa,stringGPA){
        this.gpa = gpa;
      this.stringGPA = stringGPA;

    }
stringGPA() {}
};

const student = new Student(3.9);
this.Student returnValue("3.9");

14 Answers

Julian Cobos
Julian Cobos
10,646 Points

Question: Inside the stringGPA() method, convert the value of the gpa property to a string and return it.

Your goal is to grab the gpa which is currently a number and turn it into a string. example = 12345 to "12345".

Answer:

class Student {
    constructor(gpa){
        this.gpa = gpa;
    }
    stringGPA() {
        return String(this.gpa);  
    }
}

const student = new Student(3.9);

Thank you, God bless you and your family.

God bless everyone and your family.

Alex Franklin
Alex Franklin
12,403 Points

At what point in ANY video in the lessons up to this challenge reference the use of, "toString()" ? ? ?

Steven Parker
Steven Parker
231,184 Points

While it works, it's not necessary to use "toString()" to solve the challenge.

Exactly!!!

Riaz Khan
Riaz Khan
5,320 Points
class Student {
    constructor(gpa){
        this.gpa = gpa;
    }
  stringGPA(){
    return this.gpa.toString();
  }
}

const student = new Student(3.9);
Steven Parker
Steven Parker
231,184 Points

:warning: Explicit answers without any explanation are strongly discouraged by Treehouse and may be subject to redaction by staff or moderators.

Darren Ward
Darren Ward
12,025 Points

Coming off of the front end web dev track, it feels like not everything has been explained as well as in the other tracks by the other tutors.

Steven Parker
Steven Parker
231,184 Points

It looks like you got a bit off-track The instructions say "Inside the stringGPA() method", so all the code you add for this task should all go between the braces you added in task 1.

They also say, "convert the value of the gpa property to a string and return it.". So you'll need to reference the property already created in the constructor, convert it to a string, and "return" it. You won't need to create a new property (and a property cannot have the same name as a method).

Give it another try with these things in mind.

i dont seem to understand ive been doing this challenge for a while now

Steven Parker
Steven Parker
231,184 Points

In task 1, you created a new method:
    stringGPA() {} :point_left: your method includes this pair of braces

So far task 2, all new code needs to go in between those braces. So the line you added to the constructor, and the line you added at the end should not be there.

Then, the code you add won't have any literal values in it. You need to refer to the existing property named "gpa".

You might want to re-watch the last video and take another look at the example shown there.

John Oconnell
John Oconnell
13,807 Points

This should be the top answer for sure, thanks for this. Explains WHY the code does what it does.

Steven Parker
Steven Parker
231,184 Points

Thanks, I always try to explain but let the student still solve it for themselves. I think it creates a better learning experience.

But as you see, some students still prefer explicit answers. ¯\_(ツ)_/¯

stringGPA() {
        return this.gpa.toString();
  }

Add this code to stringGPA method.

Noelle Lewis
Noelle Lewis
7,895 Points

Did anyone figure this out? Because Im having a hard time

Steven Parker
Steven Parker
231,184 Points

Several answers shown above have viable solutions!

stringGPA () {
   return String(this.gpa) // This will spit out ' this is not a function '
}
Steven Parker
Steven Parker
231,184 Points

It would by itself. That definition style can only be used as part of a class definition (as in Julian's example).

stringGPA () {
  return this.gpa.toString() // Also spit out " student.stringGPA is not a function "
}

I've try my very best. After researching from various forums, everything i do spit out This is not a function

Steven Parker
Steven Parker
231,184 Points

I tried pasting that directly into the challenge and it passed. Is it possible you've accidentally changed something else in the provided code?

O gawd! School boy mistake! I used a visual studio code to write my code rather than using the given workspace TreeHouse provide. And i copied everything that was there and paste it. Thanks again for helping out Steve!

Sundar Maharjan
Sundar Maharjan
6,740 Points

class Student { constructor(gpa){ this.gpa = gpa; } stringGPA() { return String(this.gpa);
} }

return this.gpa=‘gpa’;

My answer is similar to Salwa Elmohandes', and while her answer worked for her, it didn't work for me. By changing the single quotes ' ' around gpa to double quotes " ", it worked!

stringGPA() { return this.gpa = "gpa"; }

Jennifer Sanchez
Jennifer Sanchez
8,536 Points

I used a template literal and it worked!

class Student { constructor(gpa){ this.gpa = gpa; } stringGPA() { return (${this.gpa}); } }

const student = new Student(3.9);