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Shih Kai-Wen
613 PointsChallenge 1
I am stuck at the challenge 1, can someone help me?
def loopy(items):
# Code goes here
for thing in items:
if thing == "STOP":
break
else:
print(thing)
4 Answers
Alexandra Barnett
Front End Web Development Techdegree Graduate 46,473 PointsHi Shih! I found that, if I didn't have the else clause, it passed the challenge but it should work either way...
def loopy(items):
# Code goes here
for item in items:
if item == "STOP":
break
print(item)
Jerome Francis
1,318 Pointsdef loopy(items):
# Code goes here
for x in items:
print(items)
```
Ari Misha
19,323 PointsHiya Shih! The order of statements in a loop matters. The first statement gets executed first and followed by second statement and so on. Lets relate to this logic in the challenge. Unless your loop prints out every "item" alias in the loop , how else is it gonna get to "STOP" keyword in "items" argument. I mean it makes sense right? In your "for" loop, remove the "else" conditional first. Secondly, put print(item) statement on top, inside the loop and followed by "if" statement. If you want a code for reference , i think codes submitted in comments by Francis and Alexandra are right on money. (:
Shih Kai-Wen
613 PointsThank everyone so much, I have passed it!!