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Start your free trialKingsley Maduaka
467 Pointscatching exceptions. how do i place the variables or method in exception cases.
i tried different ways of placing the argument exceptions . really confused on how to put put the variables to avoid syntax error .
class GoKart {
public static final int MAX_BARS = 8;
private String color;
private int barCount;
private int lapsDriven;
public GoKart(String color) {
this.color = color;
}
public String getColor() {
return color;
}
public void charge() {
barCount = MAX_BARS;
}
public boolean isBatteryEmpty() {
return barCount == 0;
}
public boolean isFullyCharged() {
return MAX_BARS == barCount;
}
public void drive() {
try{
drive(1);
}catch(IllegalArgumentException iae){
System.out.println("wrong");
}
public void drive(int laps) {
try{
lapsDriven += laps;
if (laps < 0);
barCount -= laps;
}catch(IllegalArgumentException iae){
if (barCount < 1);
System.out.println("wrong");
}
}
}
1 Answer
Steven Parker
231,184 PointsHere's a few hints:
- you only need to modify the version of "drive" that takes an argument (the other one calls it)
- your test expression will need to compare the "laps" with the "barCount"
- you only need to "throw" the exception, you won't need a "try" or "catch"
- leave the original code to do what it normally does if no exception is thrown
- you won't need to print anything
Give it a shot with that in mind, and write again if you still have trouble.