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Python Python Basics (2015) Number Game App Even or Odd

Laknath Gunathilake
Laknath Gunathilake
1,860 Points
Posted by Laknath Gunathilake
Laknath Gunathilake
1,860 Points

can't seem to pass the challenge

when I run the code it says TypeError: even_odd() takes 0 positional arguments but 1 was given

even.py 
def even_odd():
    number=int(input("enter number:"))
    if number%2==0:
      return True 
    else:
      return False

1 Answer

Grigorij Schleifer
Grigorij Schleifer
10,365 Points
Grigorij Schleifer
Grigorij Schleifer
10,365 Points

Hi Laknath,

you can use this code:

you don´t need to ask the user for the number . Give the number as a method argument for the even_odd method.

def even_odd(number):
# number is the methods argument

The rest ist fine :)

Grigorij