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Python Python Basics (2015) Shopping List App Continue

Posted by Ian Maina
Ian Maina
4,571 Points

Can't seem to get anywhere with this challenge. Any tips?

Same idea as the last one. My loopy function needs to skip an item this time, though. Loop through each item in items again. If the character at index 0 of the current item is the letter "a", continue to the next one. Otherwise, print out the current member. Example: ["abc", "xyz"] will just print "xyz".

breaks.py 
def loopy(items):
    # Code goes here
    for item in items:
        if item.index([1]) == 'a':
            continue
        else:
            print(item)

1 Answer

Ted Dunn
Ted Dunn
43,783 Points
Ted Dunn
Ted Dunn
43,783 Points

The problem is with your if condition, the index method returns a value which is the integer value of the index where the supplied substring begins. Thus, you are comparing an integer to a string ("a") and it will never evaluate as True.

I would suggest the following:

for item in items:
    if item[0] == "a":
        continue
    else:
        print(item)

This code is referring to the letter at the index of zero for the item begin examined (item[0]) and comparing it to the letter "a". Thus, you are comparing a string (letter at index 0 of item) to a string ("a").