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Python Python Basics (2015) Shopping List App Continue

Aananya Vyas
Aananya Vyas
20,157 Points
Posted by Aananya Vyas
Aananya Vyas
20,157 Points

cant find the logic flaw please help

this is the challenge:

Same idea as the last one. My loopy function needs to skip an item this time, though.

Loop through each item in items again. If the character at index 0 of the current item is the letter "a", continue to the next one. Otherwise, print out the current member.

Example: ["abc", "xyz"] will just print "xyz".

breaks.py 
def loopy(items):
  for item in items: # use the singular of items as our iteration variable
    if item.index(0) == "a":
        continue
        print(item) # reduce tab count so this isn't part of the if block

1 Answer

Wade Williams
Wade Williams
24,476 Points
Wade Williams
Wade Williams
24,476 Points

You have an indent error in your code, your print statement needs to be outside of your if statement. And index() doesn't do what you think it does. You use index() to find something in a list like index("abc") and it will return the index of "abc" in the list. To get the value of an index you just use bracket notation like item[0].

All together now

def loopy(items):
    for item in items:
        if item[0] == "a":
            continue
        print(item)