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Dimitrios Exarchos
893 PointsCan't convert 'int' object to str implicitly
Seems simple to me but I get the above error.
def loopy(items):
for item in items:
if item.index(0) == "a":
continue
print (item)
2 Answers
andren
28,558 PointsThe error come from the fact that you are using the index function incorrectly. It does not take an index and return a character, it does the exact opposite. You are meant to provide it with a character and then it returns the index of said character if it exists, or throws an exception if it does not.
It's actually not a good idea to use the index function for this task. The index function is more suited for situations where you expect a character to always be present. That's why it actually throws an exception if the character is not found.
To check the first index of a string you can use the exact same technique you used in an earlier challenge to check the first item of a list (bracket notation). This is due to the fact that in Python strings are treated as lists of characters.
So you can solve the challenge like this:
def loopy(items):
for item in items:
if item[0] == 'a':
continue
print(item)
Which as you can see is pretty close to the code you had, it just uses bracket notation to get the first character rather than using the index method like you tried to do.
Dimitrios Exarchos
893 PointsThank you very much!