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5,127 Pointscan someone tell me what im doing wrong
im missing it
<?php
//edit this array
$contacts[] = array('name' => 'Alena Holligan','email'=>'alena.holligan@teamtreehouse.com');
$contacts[] = array('name' => 'Dave McFarland','email'=>'dave.mcfarland@teamtreehouse.com');
$contacts[] = array('name' => 'Treasure Porth','email'=>'treasure.porth@teamtreehouse.com');
$contacts[] = array('name' => 'Andrew Chalkley','email'=>'andrew.chalkley@teamtreehouse.com');
echo "<ul>\n";
//$contacts[0] will return 'Alena Holligan' in our simple array of names.
echo "<li>" . $contacts[0]['name'] . ":" . $contacts[0]['email'] . "</li>\n";
echo "<li>" . $contacts[1]['name'] . ":" . $contacts[1]['email'] . "</li>\n";
echo "<li>" . $contacts[2]['name'] . ":" . $contacts[2]['email'] . "</li>\n";
echo "<li>" . $contacts[3]['name'] . ":" . $contacts[3]['email'] . "</li>\n";
1 Answer
Muhammad Ehsan Hanif
8,236 PointsNothing wrong with your code. You just have to keep the proper formatting as in the hard coded code. There should be space around the semicolon similar to hard code values.
echo "<ul>\n";
//$contacts[0] will return 'Alena Holligan' in our simple array of names.
echo "<li>" . $contacts[0]['name'] . " : " . $contacts[0]['email'] . "</li>\n";
echo "<li>" . $contacts[1]['name'] . " : " . $contacts[1]['email'] . "</li>\n";
echo "<li>" . $contacts[2]['name'] . " : " . $contacts[2]['email'] . "</li>\n";
echo "<li>" . $contacts[3]['name'] . " : " . $contacts[3]['email'] . "</li>\n";
echo "</ul>\n";