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Python Python Basics (2015) Letter Game App Even or Odd Loop

Can someone help please.

Please help me

even.py
import random

start = 5

def even_odd(num):
    # If % 2 is 0, the number is even.
    if num % 2 == 0:
        print("{} is even".format(num))
    else:
        print("{} is odd".format(num))
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

while True:
    num = random.randint(1,99)
    break

1 Answer

Henrik Christensen
seal-mask
.a{fill-rule:evenodd;}techdegree
Henrik Christensen
Python Web Development Techdegree Student 38,322 Points

As I said in your previous post: You don't need to change anything in the even_odd function

import random

start = 5

def even_odd(num):  # don't change anything
    # If % 2 is 0, the number is even.  # don't change anything
    # Since 0 is falsey, we have to invert it with not.  # don't change anything
    return not num % 2  # don't change anything

while True:
    # do something here

I hope this helps :-)