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Java Java Objects Creating the MVP Conference Registration Assistant

Olha Markova
Olha Markova
2,050 Points

can not complete the task

I don´t know how to bind line Numbers to the last name letters, so that there will be returned a right one number. Maybe someone here have idea, how it can be done. Thanks!

ConferenceRegistrationAssistant.java
public class ConferenceRegistrationAssistant {

  /**
   * Assists in guiding people to the proper line based on their last name.
   *
   * @param lastName The person's last name
   * @return The line number based on the first letter of lastName
   */
  public int getLineNumberFor(String lastName) {
    int lineNumber = 0;
    /*
      lineNumber should be set based on the first character of the person's last name
      Line 1 - A thru M
      Line 2 - N thru Z

     */
    String line1 = "ABCDEFGHJKLM";
    String line2 = "NOPRSTUVWXYZ";

    lastName.charAt(0);
    lineNumber ++;
    return lineNumber;
  }
  }
Example.java
public class Example {

  public static void main(String[] args) {
    /*
      IMPORTANT:  You can compare characters using <, >. <=, >= and == just like numbers
     */
    if ('C' < 'D') {
      System.out.println("C comes before D");
    }

    if ('B' > 'A') {
      System.out.println("B comes after A");
    }

    if ('E' >= 'E') {
      System.out.println("E is equal to or comes after E");
    }

    // This code is here for demonstration purposes only...
    ConferenceRegistrationAssistant assistant = new ConferenceRegistrationAssistant();
    /*
      Remember that there are 2 lines.
      Line #1 is for A-M
      Line #2 is for N-Z
     */
    int lineNumber = 0;
    /*
      This should set lineNumber to 2 because
      The last name is Zimmerman which starts with a Z.
      Therefore it is between N-Z
     */
    lineNumber = assistant.getLineNumberFor("Zimmerman");

    /*
      This method call should set lineNumber to 1, because 'A' from "Anderson" is between A-M.
     */
    lineNumber = assistant.getLineNumberFor("Anderson");

    /*
      Likewise Charlie Brown's 'B' is between 'A' and 'M', so lineNumber should be set to 1
     */
    lineNumber = assistant.getLineNumberFor("Brown");
  }

}

2 Answers

Hi there,

You can isolate the first character by using the charAt() method on the string, as you have tried. This turns the string into an array of char - the parameter you pass in is the array index. So, for the first letter, pass in zero. You can then compare that to, say, 'M' to see if it is greater than 'M'. This allows you to set the lineNumber.

Something like:

    if(lastName.charAt(0) > 'M'){
      lineNumber = 2;
    } else {
      lineNumber = 1;
    } 

Make sense?

Steve.

Olha Markova
Olha Markova
2,050 Points

Thank you, it works!

No problem! :+1: :smile: