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Start your free trialSuleiman Abdurozikov
2,943 Pointscan anyone help
I need help
This challenge is similar to an earlier one. Remember, though, I want you to practice! You'll probably want to use try and except on this one. You might have to not use the else block, though.
Write a function named squared that takes a single argument.
If the argument can be converted into an integer, convert it and return the square of the number (num ** 2 or num * num).
If the argument cannot be turned into an integer (maybe it's a string of non-numbers?), return the argument multiplied by its length. Look in the file for examples.
what is wrong?
def squared(num1):
try:
num1=int(num1)
return(num1*num1)
else:
return(num1*len(num1))
2 Answers
Alexander Davison
65,469 PointsTry using except ValueError
instead of else
. :)
def squared(num1):
try:
num1=int(num1)
return(num1*num1)
except ValueError:
return(num1*len(num1))
Good luck! ~alex
Alexander Davison
65,469 PointsNo problem :)